Math, asked by priyanshusingh18, 10 months ago

divide the polynomial 6x power 3 -x power 2-10x-3 divided by 2x-3

Answers

Answered by saifu50

quotient=3x²+4x+1

remainder=0

BY REMAINDER THEOREM

f(x)=g(x)×q(x)+r(x)

6x³–x²–10x–3=(2x-3)(3x²+4x+1)+0

6x³–x²–10x–3=2x(3x²+4x+1)–3(3x²+4x+1)

6x³–x²–10x–3=6x³+8x²+2x–9x²–12x–3

6x³–x²–10x–3=6x³–x²–10x–3

Proved it with REMAINDER THEOREM

Attachments:

saifu50: agle saal aa jana

priyanshusingh18: year do na

saifu50: dekh bhai pehle theorem samajh

saifu50: dividend=divisor×quotient+remainder

saifu50: ye h thorem

priyanshusingh18: not like this

saifu50: to fir kaise bhai

saifu50: kaise samjhna h tumhe tum batao

saifu50: aur kya samajhna h ye bhi batao

priyanshusingh18: just see other questions I have posted before this question how they have done

Answered by kumarisangita2371986

Answer: 6x³-x²-10x-3= (2x-3)(3x²+4x-1)

Step-by-step explanation: the explanation is attached below

Hope it helps!

The answer in Rd Sharma book is wrong. This⬇️is the right answer.

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