Question

divide the polynomial 6x power 3 -x power 2-10x-3 divided by 2x-3​

Answer 1

quotient=3x²+4x+1

remainder=0

BY REMAINDER THEOREM

f(x)=g(x)×q(x)+r(x)

6x³–x²–10x–3=(2x-3)(3x²+4x+1)+0

6x³–x²–10x–3=2x(3x²+4x+1)–3(3x²+4x+1)

6x³–x²–10x–3=6x³+8x²+2x–9x²–12x–3

6x³–x²–10x–3=6x³–x²–10x–3

Proved it with REMAINDER THEOREM

Answer 2

Answer: 6x³-x²-10x-3= (2x-3)(3x²+4x-1)

Step-by-step explanation: the explanation is attached below

Hope it helps!

The answer in Rd Sharma book is wrong. This⬇️is the right answer.