Divide the Polynomial 6x²-5x² +2x -3 by x-2
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You can try by Factor Theorum !
x-2 = 0
x = 2
p(x) = 6x²- 5x² + 2x -3 x = 2
substituting the value 2 we get
p(2) = 6(2)²- 5(2)²+2(2)-3
= 6(4)-5(4)+2(2)-3
= 24 - 20 + 4 -3
= 24+4 -20-3
= 28 -23
= 5
Hence the remainder is 5
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