Question

divide the polynomial : p(x) =x³-3x²+2+x ; g(x) =x²-x+1​

Answer 1

Answer:

x³-3x²+5x-3 ÷ x²-2

x - 3

x² - 0x² -2 ∫x³ - 3x² + 5x -3

- (x³ - 0x² - 2x)

- 3x² + 7x - 3

- ( -3x² + 0x + 6)

7x - 9

Quotient = x - 3

Reminder comes = 7x -9

mark me as brain list power

Answer 2

$\huge\mathfrak\blue{ANSWER}$

p(x) = g(x)*q(x) + r(x)

x³-3x²+x+2 = g(x)*[x-2] -2x +4

x³-3x²+x+2+2x-4 = g(x)*[x-2]

x³-3x²+3x-2 / [x-2] = g(x)

therefore g(x) = x²-x+1