Question

divide the polynomial x²-10x+21 by each of the following divisors and find the remainder in each case: (1) x+2, (2) x-3, (3) x+5, (4) x-7​

Answer 1

Answer:

Step-by-step explanation:

Just by using remainder theorem put the value of x in p(x)=x²-10x+21

P(-2)= 45 as remainder

P(3)= 0 as remainder

P(-5)=76 as remainder

P(7)= 0 as remainder