Question

divide the polynomial x3-6x2+11x-6 by (x-3) and check whether (x-3) is a factor of the polynomial

Answer 1

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Answer 2

The quotient is x²- 3x + 2 and remainder is 0

GIVEN

Polynomial- x³ - 6x² + 11x - 6

Divisor = (x-3)

TO FIND

To divide the given equations and check wether the divisor is the factor of the polynomial.

SOLUTION

The above problem can be simply solved as follows;

GIVEN,

Dividend = x³ - 6x² + 11x - 6

Divisor = (x-3)

Carrying the division-

x²- 3x + 2

x-3 )x³ - 6x² + 11x - 6

-x³ + 3x²

-3x² + 11x - 6

+3x² + 9x

2x - 6

-2x + 6

0

Since on division, the remainder is 0.

Therefore, (x-3) is a factor of the given polynomial.

Hence, The quotient is x²- 3x + 2 and remainder is 0

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