Math, asked by mahalaxmin2006, 6 months ago

divide the polynomial x3-9x2+23x-18 by x2-4x+3and find the quotient and the remainder

Answers

Answered by akankshaahire1904
0

Answer:

Set up a table with the coefficients of the dividend on the first row (

row A

below) leaving a little extra space at the beginning of the line.

Leave a blank line (to be filled in as we go along).

Write the negative of the divisor at the far left of the third line (

row C

below).

You should have something that looks like:

XXXX

x

3

XX

x

2

XX

x

1

XX

x

0

XXx

XX

1

XX

9

XX

23

XX

15

X

row A

xxx

XXXXXXXXXXXX

−−−−−−−−−−−−−−−−−−−−−−−

row B

5

x

XXXXXXXXXXXXXX

row C

For each coefficient column in turn from left to right:

Add the value in

row B

to the (coefficient) value in

row A

and write the result in

row C

Multiply the negative divisor (on the far left of

row C

) by the value just written in

row C

and writer the product in the next column of

row B

After processing the first column, your result should look like:

XXx

XX

1

XX

9

XX

23

XX

15

X

row A

XXx

XXxx

5

XXXXXXX

−−−−−−−−−−−−−−−−−−−−−−−−

row B

5

x

X

1

XXXXXXXXXXXx

row C

...and after processing all the columns, like:

XXx

XX

1

XX

9

XX

23

XX

15

X

row A

XXx

XXxx

5

x

20

x

15

−−−−−−−−−−−−−−−−−−−−−−−−−

row B

5

x

X

1

XX

4

XXX

3

XX

0

X

row C

The final result in

row C

gives the coefficients of the resulting quotient plus (as the last value in

row C

the remainder:

5

x

X

1

XX

4

XXX

3

−−−−−−−−−−−

XX

0

XXXXXXX

row C

XXXX

x

2

XX

x

1

XX

x

0

XX

Remainder

Similar questions