Math, asked by bhiyalalyadav442, 8 months ago

Divide the polyomial 3x^4-4x^3-3x-1 by x-1​

Answers

Answered by rainasuman917
0

Answer

Divide the polynomial 3x^4 - 4x^3 -3x-1 by (x-1) and find its quotient and remainder

2

Your answer is in the attachment...⬆⬆

Hope it helps you...

THANKS ^-^

Answer:

Dividend = 3x⁴-4x³-3x-1

Divisor = x - 1

Quotient = 3x³-x²-x-4

Remainder = -5

Step-by-step explanation:

Given (3x⁴-4x³-3x-1)÷(x-1)

Quotient : 3x³-x²-x-4

x-1) 3x⁴-4x³+0-3x-1

**** 3x⁴-3x³

______________________

*******-x³+0

******* -x³ + x²

______________________

*********** -x² -3x

********** -x² + x

______________________

*********** -4x - 1

************ -4x +4

______________________

******Remainder ( -5 )

Therefore,

Dividend = 3x⁴-4x³-3x-1

Divisor = x - 1

Quotient = 3x³-x²-x-4

Remainder = -5

Thanks

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