Question

Divide the rupees 1050 in the ratio 7:8​

Answer 1

let 7:8 as 7x and 8x

7x + 8x =1050

15x=1050

x=1050/15

x=70

7x=7×70=490

8x=8×70= 560

the ratio is 490:560

Answer 2

Answer:

Required first part of 1050 rupees is 490 rupees and second part of 1050 rupees is 560 rupees.

Step-by-step explanation:

Given,total amount 1050 rupees.

Here we want to divide 1050 rupees in the ratio 7:8.

Let, first part of the money be 7x rupees and second part of the money be 8x rupees.

Now total amount

$= (7x + 8x) \\ = 15x \: \: rupees$

According to question,

$15x = 1050 \\ x = \frac{1050}{15} \\ x = 70$

Therefore first part of 1050 rupees is (7×70) = 490 rupees and second part of 1050 rupees is (8×70) = 560 rupees.

This is a problem of ratio of Algebra.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

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