Divide the rupees 1050 in the ratio 7:8
Answers
let 7:8 as 7x and 8x
7x + 8x =1050
15x=1050
x=1050/15
x=70
7x=7×70=490
8x=8×70= 560
the ratio is 490:560
Answer:
Required first part of 1050 rupees is 490 rupees and second part of 1050 rupees is 560 rupees.
Step-by-step explanation:
Given,total amount 1050 rupees.
Here we want to divide 1050 rupees in the ratio 7:8.
Let, first part of the money be 7x rupees and second part of the money be 8x rupees.
Now total amount
According to question,
Therefore first part of 1050 rupees is (7×70) = 490 rupees and second part of 1050 rupees is (8×70) = 560 rupees.
This is a problem of ratio of Algebra.
Some important Algebra formulas.
(a + b)² = a² + 2ab + b²
(a − b)² = a² − 2ab − b²
(a + b)³ = a³ + 3a²b + 3ab² + b³
(a - b)³ = a³ - 3a²b + 3ab² - b³
a³ + b³ = (a + b)³ − 3ab(a + b)
a³ - b³ = (a -b)³ + 3ab(a - b)
a² − b² = (a + b)(a − b)
a² + b² = (a + b)² − 2ab
a² + b² = (a − b)² + 2ab
a³ − b³ = (a − b)(a² + ab + b²)
a³ + b³ = (a + b)(a² − ab + b²)
Know more about Algebra,
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