Question

divide the s of 75/12 by their difference 7/3 by their difference​

Answer 1

TO FIND :-

$(\frac{75}{12}+\frac{7}{3})\div (\frac{75}{12} - \frac{7}{3} )\\ \\= (\frac{75 + 28}{12}) \div (\frac{75 - 28}{12}) \\ \\= \frac{103}{12} \div\frac{47}{12}\\ \\= \frac{103}{12} \times\frac{12}{47}\\ \\= \frac{103}{47}\\ \\= 2\frac{9}{47}\\ \\= 2.1914(approx)$

STEPS INVOLVED :-

1. According to the question , first we will add 75/12 and 7/3 by taking LCM at denominator and adding numerator accordingly.

2. Similarly we will subtract the smaller fraction 7/3 from the larger fraction i.e. 75/12.

3. Finally we will divide the result as per the question.

4.In division we will reciprocal the second number and multiply it with first fraction.

5. 12 is cancelled out and the result is 103/47 which is converted to mixed fraction and decimal .

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