Question

divide the sum of 1/4 and 3/2 by their difference​

Answer 1

$\huge \mathbb\fcolorbox{black}{mistyrose}{Answer}$

Step-by-step explanation:

$the \: sum \: \\ \frac{1}{4} + \frac{1}{3} \\ \frac{3 + 4}{12} \\ \frac{7}{12} \\ the \: difference \\ \frac{1}{4} - \frac{1}{3} \\ \frac{3 - 4}{12} \\ \frac{ - 1}{12} \\ their \: division \\ \frac{7}{12} \div ( - \frac{1}{12}) \\ \frac{7}{12} \times ( - 12) \\ - 7$