Question

Divide the sum of -2 15/17 and 3 5/34 by their difference.

Answer 1

Step-by-step explanation:

=>-2 15/17(-2×15+17)= -49/17

=>3 5/34(3×4+5)=17/34

☆Then take the L.C.M. to make the denominators same.☆

L.C.M. of 17 and 34=2×17=34

_____________________________

=> -49/17×2/2= -98/34

=>17/34×1/1=17/34

Now add them:-

(-98+17)/34=> -81/34

Subtract them:-

(-98-17)/34= -115/34

Now divide the answers we get after adding and subtracting them:-

-81/34÷ -115/34

Take reciprocal of -115/34

=>-81/34×(reciprocal of -115/34)

=>-81/34×34/115

=> -81/115

Answer 2

Answer:

The given question has mixed fraction. So first we should change this mixed fraction into improper fraction. Then only we can find the divide the sum of $-2\frac{15}{17}$ and $3\frac{5}{34}$ by their difference. Answer: $\frac{-69}{145}$

Step-by-step explanation:

• First step we should convert mixed fraction into improper fraction.

                      $-2\frac{15}{17}=\frac{(-2)*17+15}{17}$

                                $=\frac{(-34)+15}{17}$

                       $-2\frac{15}{17}=\frac{-19}{17}$

      similarly,     $3\frac{5}{34}=\frac{3*34+5}{34}$

                                $=\frac{102+5}{34}$

                         $3\frac{5}{34}=\frac{107}{34}$

• Next we should find the sum of $\frac{-19}{17}$ and $\frac{107}{34}$. But denominator are different. So we take L.C.M for 17 and 34.
• L.C.M of 17 and 34 is, 34

                 $\frac{-19}{17}+\frac{107}{34}=\frac{(-19*2)}{34}+\frac{107}{34}$

                                 $=\frac{(-38)}{34}+\frac{107}{34}$

                 $\frac{-19}{17}+\frac{107}{34}=\frac{69}{34}$      ----------------(1)

• Next we should find difference between $\frac{-19}{17}$ and $\frac{107}{34}$.

                 $\frac{-19}{17}-\frac{107}{34}=\frac{(-19*2)}{34}-\frac{107}{34}$

                                 $=\frac{(-38)}{34}-\frac{107}{34}$

                 $\frac{-19}{17}-\frac{107}{34}=\frac{-145}{34}$   ------------------(2)      

• Now we can divide equation(1) and equation(2).

                                  $=\frac{\frac{69}{34} }{\frac{-145}{34} }$

• It can written in the following form using reciprocal concept.

                          $\frac{\frac{69}{34} }{\frac{-145}{34} }=\frac{69}{34}*(\frac{34}{-145} )$

• Cancel 34 in the numerator and denominator. That is,

                 $\frac{69}{34}*(\frac{34}{-145} )=\frac{69}{-145}$

• Final Answer: Divide the sum of $-2\frac{15}{17}$ and $3\frac{5}{34}$ by their difference: $\frac{-69}{145}$