Question

Divide the sum of 2/5/12 −(19/4)by the difference of 3/7/8 (−11/24)

Answer 1

Answer -

• -7/13.

What to do -

• Divide the sum of 2 5/12 and -19/4 by the difference of 3 7/8 and -11/24.

Step-by-step explanation -

• Before finding out our answer, let's find the sum of 2 5/12 and -19/4!

$\rm\dashrightarrow 2 \: \dfrac{ \: 5}{12} + \dfrac{ - 19}{ \: \: \: \: 4}$

$\rm\dashrightarrow \dfrac{29}{12} + \dfrac{ - 19}{ \: \: \: \: 4}$

$\dashrightarrow \dfrac{(29 \times 1) + ( - 19 \times 3)}{12}$

$\dashrightarrow \dfrac{29 - 57}{12}$

$\dashrightarrow \dfrac{ - 28}{ \: \: \: 12}$

$\dashrightarrow \dfrac{ - 7}{ \: \: \: 3}$

• Now let's find the difference of 3 7/8 and -11/24!

$\dashrightarrow 3 \: \dfrac{7}{8} - \dfrac{ - 11}{ \: \: \: 24}$

$\dashrightarrow \dfrac{31}{8} - \dfrac{ - 11}{ \: \: \: 24}$

$\dashrightarrow \dfrac{(31 \times 3) - ( - 11 \times 1)}{24}$

$\dashrightarrow \dfrac{93 + 11}{24}$

$\dashrightarrow \dfrac{104}{24}$

$\dashrightarrow \dfrac{13}{3}$

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• Finally, let's divide -43/12 by 13/3!

$\implies \bf\dfrac{ - 7}{ \: \: \: 3} \div \dfrac{13}{ \: \: 3}$

$\implies \bf \dfrac{ - 7}{ \: \: \: \not\!3} \times \dfrac{ \: \: \!\not3}{13}$

$\bf\implies \dfrac{ - 7}{ \: \: \: 1} \times \dfrac{1}{13}$

$\implies \bf \dfrac{ - 7}{ \: \: \: 13}$

Hence -

• The required number is -7/13.

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