Question

divide the sum of 3/11 and 2/5 by their product​

Answer 1

◙ Sum of 3/11 and 2/5 :-

$\displaystyle{\sf{\frac{3}{11} +\frac{2}{5} }}\\\\\sf{Taking\ LCM:}\\\\\displaystyle{\sf{=\frac{3(5)+2(11)}{55} }}\\\\\displaystyle{\sf{=\frac{15+22}{55} }}\\\\\displaystyle{\sf{=\frac{37}{55} }}$

$\rule{140}2$

◙ Product of 3/11 and 2/5 :-

$\displaystyle{\sf{\frac{3}{11}\times\frac{2}{5} }}\\\\\displaystyle{\sf{=\frac{6}{55} }}$

→ Dividing sum by product :-

$\displaystyle{\sf{\frac{37}{55}\div \frac{6}{55} }}\\\\\displaystyle{\sf{=\frac{37}{55}\times\frac{55}{6} }}\\\\\sf{55\ gets\ cancelled :}\\\\\boxed{\boxed{\displaystyle{\sf{=\frac{37}{6} }}}}\:\:\:\: \cdots \bold{ANSWER}$

Mark as the brainliest ☺

Answer 2

3/11 + 2/5

LCM = 55

Therefore sum is = 37 / 55

product = 3/11(2/5) = 6/55

by dividing both we get:

37/55 ÷ 6/55

37/55 × 55/6 ---------> reciprocal

therefore by eliminating 55 we get

37/6

-------thanks:)-----------