divide the sum of 3\5 and -7\2
Answers
Answered by
0
Answer:
Sum of the numbers
S=\frac{3}{5}+\frac{8}{11}S=
5
3
+
11
8
S=\frac{33+40}{55}S=
55
33+40
S=\frac{73}{55}S=
55
73
Difference of the numbers
D=\frac{3}{5}-\frac{8}{11}D=
5
3
−
11
8
D=\frac{33-40}{55}D=
55
33−40
D=\frac{-7}{55}D=
55
−7
Now, Dividing sum by difference
\frac{S}{D}= \frac{\frac{73}{55}}{\frac{-7}{55}}
D
S
=
55
−7
55
73
\frac{S}{D}= \frac{73\times55}{55\times(-7)}
D
S
=
55×(−7)
73×55
\frac{S}{D}= \frac{73}{-7}
D
S
=
−7
73
Therefore, The required solution is \frac{S}{D}=-\frac{73}{7}
D
S
=−
7
73
Similar questions