Question

divide the sum of 3/8 and - 5/12 by the reciprocal of - 15/8*16/27​

Answer 1

Step-by-step explanation:

{3/8 + ( -5/12)} ÷( reciprocal of -15/8 x 16/27)

{(9 - 10)/24 }÷( reciprocal of -10/9)

-1/24 ÷ -9/10

-1/24 × -10/9

5/108

Answer 2

${\huge{\boxed{\sf{\green{Question}}}}}$

Divide the sum of 3/8 and - 5/12 by the reciprocal of - 15/8*16/27​

${\huge{\underline{\bf{\pink{➵ANSWER :-​✵}}}}}$

The value of the sum of 3/8 and (-5/12) by the reciprocal of (-15/8 × 16/27) is 5/108..

Solution:

Sum of

$\begin{gathered}\begin{array} { c } { \frac { 3 } { 8 } \text { and } - \frac { 5 } { 12 } = \frac { 3 } { 8 } + \left( - \frac { 5 } { 12 } \right) = \frac { 3 } { 8 } - \frac { 5 } { 12 } = \frac { 9 - 10 } { 24 } = - \frac { 1 } { 24 } } \\\\ { - \frac { 15 } { 8 } \times \frac { 16 } { 27 } = - \frac { 10 } { 9 } } \end{array}\end{gathered} 83​ and − 125​ = 83​ +(− 125​ )= 83​ − 125​ = 249−10​ =− 241​ − 815​ × 2716​ =− 910$

And, reciprocal of $-\frac{10}{9} =-\frac{9}{10}− 910​ =− 109$

Hence, on dividing-$-\frac{1}{24} and -\frac{9}{10}− 241​$ and−

10

9

$= - \frac { 1 } { 24 } \div - \frac { 9 } { 10 } = \frac { 1 } { 24 } \times \frac { 10 } { 9 } = \frac { 5 } { 108 }=− 241​ ÷− 109​ = 241​ × 910​ = 1085$

Hence the answer is 1085!