Divide the sum of 3/8 and _5/12 by the reciprocal of _15/8 ×16/27
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Solution:
i) Sum of 3/8 and 5/12
= (3/8)+(5/12)
LCM (8,12) = 24
= (9+10)/24
= 19/24 ----(1)
ii) (15/8)×(16/27)
= (3×5×2×8)/(8×3×9)
After cancellation, we get
= 10/9 -----(2)
iii ) Reciprocal of [(15/8)(16/27)
= Reciprocal of (10/9)
= 9/10 ----(3)
According to the problem given,
Divide the sum of 3/8 and _5/12 by the reciprocal of _15/8 ×16/27
= (1)/(3)
= (19/24) ÷ (9/10)
= (19/24) × (10/9)
= (19 × 2×5)/(2×12×9)
After cancellation,we get
= 95/108
••••••
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