Question

divide the sum of 3/8and-5/12by the reciprocal of -15/8×16/27​

Answer 1

Answer:

$\frac{3}{8} + \frac{ - 5}{12} \\ \\ = \geqslant \frac{3 + ( - 10)}{24} \\ \\ = \geqslant \frac{3 - 10}{24} \\ \\ = \geqslant \frac{ - 7}{24}$

and it has to being divide by Reciprocal of

$\frac{ - 15}{8} \times \frac{16}{27} \\ \\ = \geqslant \frac{ - 15}{1} \times \frac{2}{27} \\ \\ = \geqslant \frac{ - 5}{1} \times \frac{2}{9} \\ \\ = \geqslant \frac{ - 10}{9}$

and reciprocal of

$\frac{ - 10}{9} \: is \: \frac{ - 9}{10}$

Now

$\frac{ - 7}{24} \div \frac{ - 9}{10} \\ \\ = \geqslant \frac{ - 7}{24} \times \frac{ - 10}{9} \\ \\ = \geqslant \frac{35}{108}$