Question

divide the sum of ³by⁴ and ⁷by¹² their product

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pls ans​

Answer 1

Answer:

Sum =

$\frac{3}{4} + \frac{7}{12} \\ \\ \frac{9 + 7}{12} \\ \\ \frac{16}{12} \\ \\ \frac{4}{3}$

Product =

$\frac{3}{4} \times \frac{7}{12} \\ \\ \frac{1}{4} \times \frac{7}{4} \\ \\ \frac{7}{16}$

Division =

$\frac{7}{16} \div \frac{4}{3} \\ \\ \frac{7}{16} \times \frac{3}{4} \\ \\ \frac{21}{64}$

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Answer 2

$\frac{3}{4} + \frac{7}{12} \\ \\ = \frac{4}{3} \\ \\ \frac{3}{4} \times \frac{7}{12} \\ \\ = \frac{7}{16} \\ \\ \frac{7}{16} \div \frac{4}{3} \\ \\ \frac{7}{16} \times \frac{3}{4} \\ \\ = \frac{21}{64}$

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