divide the sum of 4/13 and -3/2 by their product
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Answered by
94
Let us first find the sum of 4/13 and -3/2
For this, we must take 2 and 13's LCM
it is 26
(2/2 x 4/13) + (13/13 x -3/2)
8/26 + -39/26
8/26 - 39/26
= -31/26
Let us find the product of the two numbers
4/13 x -3/2
= -12/26
Now, let us divide the sum by the product
= -31/26 ÷ -12/26
= -31/26 x 26/-12
= -31/-12
= 31/12
For this, we must take 2 and 13's LCM
it is 26
(2/2 x 4/13) + (13/13 x -3/2)
8/26 + -39/26
8/26 - 39/26
= -31/26
Let us find the product of the two numbers
4/13 x -3/2
= -12/26
Now, let us divide the sum by the product
= -31/26 ÷ -12/26
= -31/26 x 26/-12
= -31/-12
= 31/12
akhilrasheed16:
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Answered by
101
Sum of 4/13 and -3/2:-
→ 4/13+(-3/2)
→ 4/13-3/2
→ 4/13×2/2 - 3/2×13/13
→ 8/26 - 39/26
→ (8-39)/26
→ -31/26
Product :-
→ (4/13)(-3/2)
→ -6/13
Their sum/product :-
→ -31/26 ÷ -6/13
→ -31/26×13/(-6)
→ 31/2×6
→ 31/12
Hope it helps...
→ 4/13+(-3/2)
→ 4/13-3/2
→ 4/13×2/2 - 3/2×13/13
→ 8/26 - 39/26
→ (8-39)/26
→ -31/26
Product :-
→ (4/13)(-3/2)
→ -6/13
Their sum/product :-
→ -31/26 ÷ -6/13
→ -31/26×13/(-6)
→ 31/2×6
→ 31/12
Hope it helps...
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