Math, asked by afroz5, 1 year ago

divide the sum of 4/13 and -3/2 by their product

Answers

Answered by akhilrasheed16
94
Let us first find the sum of 4/13 and -3/2
For this, we must take 2 and 13's LCM
it is 26

(2/2 x 4/13) + (13/13 x -3/2)
 8/26  +  -39/26
8/26   -  39/26
= -31/26

Let us find the product of the two numbers
4/13 x -3/2
= -12/26

Now, let us divide the sum by the product
= -31/26 ÷ -12/26
= -31/26 x 26/-12
= -31/-12
= 31/12

akhilrasheed16: Mark as brainliest if this helped you
Answered by snehitha2
101
Sum of 4/13 and -3/2:-

→ 4/13+(-3/2)

→ 4/13-3/2

→ 4/13×2/2 - 3/2×13/13

→ 8/26 - 39/26

→ (8-39)/26

→ -31/26

Product :-

→ (4/13)(-3/2)

→ -6/13

Their sum/product :-

→ -31/26 ÷ -6/13

→ -31/26×13/(-6)

→ 31/2×6

→ 31/12

Hope it helps...
Similar questions