Question

Divide the sum of 43/12 and 7/3 by their differance​

Answer 1

Answer:

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Answer 2

Answer:

$= > 4 \frac{11}{15}$

Step-by-step explanation:

$sum = > \\ \\ = > \frac{43}{12} \: + \: \frac{7}{3} \\ = > \frac{43}{12} + \frac{28}{12} \\ = > \frac{43 + 28}{12} \\ = > \frac{71}{12}$

$subtraction = > \\ \\ = > \frac{43}{12} - \frac{7}{ 3} \\ = > \frac{43}{12} - \frac{28}{12} \\ = > \frac{43 - 28}{12} \\ = > \frac{15}{12}$

$division = > \\ \\ = > \frac{ \frac{71}{12} }{ \frac{15}{12} } \\ \\ = > \frac{71}{12} \times \frac{12}{15} \\ 12 \: canceled \: by \: 12 \\ = > \frac{71}{15} = 4 \frac{11}{15}$

hope it helps you.

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