Divide the sum of 43/12and 7/3by their differences
Answers
Answered by
2
43/12+7/3 = 129+84/36= 213/36=71/12
43/12-7/3=129-84/36=45/36=15/12
71/12÷15/12=71/12*12/15=71/15
43/12-7/3=129-84/36=45/36=15/12
71/12÷15/12=71/12*12/15=71/15
Similar questions
Math,
7 months ago
Physics,
7 months ago
Business Studies,
1 year ago
Biology,
1 year ago
English,
1 year ago