Question

divide the sum of 5 upon 6 and minus 4 upon 5 by their product​

Answer 1

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Answer 2

Answer:

Sum of $\frac{5}{6}$ and$\frac{-4}{5}$ divided by their product = = $\frac{-1}{20}$

Step-by-step explanation:

Given fractions are

$\frac{5}{6}$ and$\frac{-4}{5}$

Required to

Divide the sum of $\frac{5}{6}$ and$\frac{-4}{5}$ by their product

Solution:

Sum of  $\frac{5}{6}$ and $\frac{-4}{5}$  = $\frac{5}{6} + \frac{-4}{5}$

LCM (5,6) = 30, since 5 and 6 are coprime

$\frac{5}{6}$ + $\frac{-4}{5}$ =  $\frac{1}{30}$

Product of  $\frac{5}{6}$ and $\frac{-4}{5}$ = $\frac{-20}{30}$

$\frac{Sum\ of \ the \ numbers}{Product\ of \ the \ numbers}$ = $\frac{\frac{5}{6} +\frac{-4}{5} }{\frac{5}{6} X\frac{-4}{5} }$

=$\frac{\frac{1}{30} }{\frac{-20}{30} }$

= $\frac{-1}{20}$

∴ Sum of $\frac{5}{6}$ and$\frac{-4}{5}$ divided by their product = = $\frac{-1}{20}$

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