Question

divide the sum of 51/17 and 11/3 by their difference ​

Answer 1

☯GIVEN :

• Divide the sum of $\bf {\dfrac {51} {17}}$ and $\bf {\dfrac {11} {3}}$ by their difference.

➲SOLUTION :

Sum of $\bf {\dfrac {51} {17}}$ and $\bf {\dfrac {11} {3}}$ :

$\implies \sf{ \dfrac{51}{17} + \dfrac{11}{3} }$

$\implies \sf{ \dfrac{51 \times 3 + 11 \times 17}{51} }$

$\implies \sf{ \dfrac{153 + 187}{51} }$

$\implies \sf{ \cancel{\dfrac{ 340}{51}} }$

$\implies \sf{ \bf{ \pink {\dfrac{ 20}{3} } }}$

Difference of $\bf {\dfrac {11} {3}}$ and $\bf{\dfrac {51} {17}}$ :

$\implies \sf{ \dfrac{11}{3} - \dfrac{51}{17} }$

$\implies \sf{ \dfrac{11 \times 17 - 51 \times 3}{51} }$

$\implies \sf{ \dfrac{187-153 }{51} }$

$\implies \sf{ \cancel{\dfrac{ 34}{51}} }$

$\implies \sf{ \bf{ \pink {\dfrac{ 2}{3} } }}$

Dividing the sum of $\bf {\dfrac {51} {17}}$ and $\bf {\dfrac {11} {3}}$ by their difference.

$\implies\sf{Sum \div Difference}$

$\implies\sf{ \dfrac{20}{3} \div \dfrac{2}{3} }$

$\implies\sf{ \dfrac{\cancel{20}}{\cancel{3}} \times \dfrac{ \cancel {3}}{\cancel{2}} }$

$\implies \underline{ \huge{ \boxed{\bf{ \green{10}}}}}$

Answer 2

Answer:

divide the sum of 51/17 and 11/3 by their defference