divide the sum of 65 / 12 and 8 / 3 by their defence?
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Divide the sum of 65/12 and 8/3 by their difference =\frac{97}{33}
Step-by-step explanation:
Let A=\frac{65}{12}\: and \:</p><p>B = \frac{8}{3}
i ) Sum =A+B = \frac{65}{12}+\frac{8}{3}
=\frac{65+32}{12}
=\frac{97}{12} ---(1)
ii) Difference = A-B=\frac{65}{12}-\frac{8}{3}
=\frac{65-32}{12}
=\frac{33}{12} ---(2)
According to the problem given,
\frac{A+B}{A-B}
= \frac{\frac{97}{12}}{\frac{33}{12}}
= \frac{97}{33}
Therefore,
Divide the sum of 65/12 and 8/3 by their difference =\frac{97}{33}
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