Question

DIVIDE THE SUM OF 65/12 AND 8/3 BY THEIR DIFFERENCE.​

Answer 1

Answer:

Sum :

$\frac{65}{12} + \frac{8}{3}$

$\frac{65 + 32}{12}$

$= \frac{97}{12}$

Difference:

$\frac{65}{12} - \frac{8}{ 3}$

$\frac{65 - 32}{12}$

$\frac{33}{12}$

$= \frac{11}{4}$

Dividing the sum by difference:

$\frac{97}{12} \div \frac{11}{4}$

$\frac{97}{12} \times \frac{4}{11}$

$\frac{97}{33}$

=2.93