Question

divide the sum of 65/12 and 8/3 by their difference?​

Answer 1

Answer:

$\frac{65}{12} + \frac{8}{3} = \frac{65 + 32}{12} = \frac{97}{12} \\ \frac{65}{12} - \frac{8}{3} = \frac{65 - 32}{12} = \frac{33}{12} \\ \frac{97}{12} \div \frac{33}{12} = \frac{97}{12} \times \frac{12}{33} = \frac{97}{33} \:$