Question

Divide the sum of 65/12 and 8/3 by their different

Answer 1

Answer:

Divide the sum of 65/12 and 8/3 by their difference =\frac{97}{33}

33

97

Step-by-step explanation:

Let A=\frac{65}{12}\: and \: B = \frac{8}{3}A=

12

65

andB=

3

8

i ) Sum =A+B = \frac{65}{12}+\frac{8}{3}A+B=

12

65

+

3

8

=\frac{65+32}{12}

12

65+32

=\frac{97}{12}

12

97

---(1)

ii) Difference = A-B=\frac{65}{12}-\frac{8}{3}A−B=

12

65

−

3

8

=\frac{65-32}{12}

12

65−32

=\frac{33}{12}

12

33

---(2)

According to the problem given,

\frac{A+B}{A-B}

A−B

A+B

= \frac{\frac{97}{12}}{\frac{33}{12}}

12

33

12

97

= \frac{97}{33}

33

97

Therefore,

Divide the sum of 65/12 and 8/3 by their difference =\frac{97}{33}

33

97

Answer 2

Answer:

$\frac{97}{33}$

Step-by-step explanation:

$\frac{65}{12} \: and \: \frac{8}{3} \\ \\ sum - \\ \frac{65}{12} + \frac{8}{3} = \frac{65 + 32}{12} = \frac{97}{12} \\ \\ difference - \\ \frac{65}{12} - \frac{8}{3} = \frac{65 - 32}{12} = \frac{33}{12} \\ \\ dividing \: sum \: by \: difference \\ \\ \frac{97}{12} \div \frac{33}{12} = \frac{97}{12} \times \frac{12}{33} = \frac{97}{33}$

hopefully this will help you !!!!

please mark my answer brainliest if you like it plz support me and support me

thank you !!!!