Question

Divide the sum of 65/12and8/3 by their difference

Answer 1

Hello ,

First,
Let us find the sum,
$\frac{65}{12} + \frac{8}{3} \\ \frac{65 + 32}{12} \\ \frac{97}{12}$

Now let's find the difference,
$\frac{65}{12} - \frac{8}{3} \\ \frac{65 - 32}{12} \\ \frac{33}{12}$
Finally let's divide them,
$\frac{97}{12} \div \frac{33}{12} \\ \frac{97}{12} \times \frac{12}{33} \\ \frac{97}{33} \\ 2 \frac{31}{33}$