divide the sum of 65/9 and-11/-3 by the product of 7/6 and 5/-3
Answers
Answered by
46
sum of 65/9 and -11/-3 or 11/3 [as -ve/-ve = +ve]
= 65/9 + 11/3
= (65+33)/9
=98/9
Product of 7/6 and 5/-3
= 7/6 × -5/3
= -35/18
Dividing 98/9 by -35/18 =>
98/9 ÷ -35/18
= 98/9 × -18/35
=(98 × (-2))/35
=-196/35
= -28/5
Answer) -28/5
= 65/9 + 11/3
= (65+33)/9
=98/9
Product of 7/6 and 5/-3
= 7/6 × -5/3
= -35/18
Dividing 98/9 by -35/18 =>
98/9 ÷ -35/18
= 98/9 × -18/35
=(98 × (-2))/35
=-196/35
= -28/5
Answer) -28/5
zerodown1024:
Is it fine now?
thankkkuu
how u got -2
bro , -18/9 = -2
i am not bro i am girl 7th
nyc answer
Answered by
24
sum of 65/9 and 11/3(-11/-3=11/3)
LCM of 9 and 3 = 9
so, 11/3 = 33/9
= (65+33)/9
= 98/9
product of 7/6 and 5/-3
= -35/18
on dividing
98/9 ÷ -35/18
= 98/9 × -18/35
= (98 × -2)/ 35
= -196/ 35
= -28/5
so answer is -28/5
LCM of 9 and 3 = 9
so, 11/3 = 33/9
= (65+33)/9
= 98/9
product of 7/6 and 5/-3
= -35/18
on dividing
98/9 ÷ -35/18
= 98/9 × -18/35
= (98 × -2)/ 35
= -196/ 35
= -28/5
so answer is -28/5
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