Question

divide the sum of 65/9 and-11/3 by the product of 7/6 and 5/-3

Answer 1

SOLUTION:-

Given:

Divide the sum of 65/9 & -11/3 by the product of 7/6 & 5/-3.

So, firstly sum;

$= > \frac{65}{9} + \frac{( - 11)}{3} \\ \\ = > \frac{65 + ( - 33)}{9} \\ \\ = > \frac{65 - 33}{9} \\ \\ = > \frac{32}{9}$

And, we can find Product:

$= > \frac{7}{6} \times \frac{5}{ - 3} \\ \\ = > \frac{35}{ - 18}$

Now,

Divide:

$= > \frac{32}{9} \div \frac{35}{ - 18} \\ \\ = > \frac{32}{9} \times \frac{ - 18}{35} \\ \\ = > \frac{ - 64}{35}$

Hope it helps ☺️