divide the sum of 65upon12 and 8 upon 3 by their differences
Answers
Answer:
Answer:
Divide the sum of 65/12 and 8/3 by their difference =\frac{97}{33}
33
97
Step-by-step explanation:
Let A=\frac{65}{12}\: and \: B = \frac{8}{3}A=
12
65
andB=
3
8
i ) Sum =A+B = \frac{65}{12}+\frac{8}{3}A+B=
12
65
+
3
8
=\frac{65+32}{12}
12
65+32
=\frac{97}{12}
12
97
---(1)
ii) Difference = A-B=\frac{65}{12}-\frac{8}{3}A−B=
12
65
−
3
8
=\frac{65-32}{12}
12
65−32
=\frac{33}{12}
12
33
---(2)
According to the problem given,
\frac{A+B}{A-B}
A−B
A+B
= \frac{\frac{97}{12}}{\frac{33}{12}}
12
33
12
97
= \frac{97}{33}
33
97
Therefore,
Divide the sum of 65/12 and 8/3 by their difference =\frac{97}{33}
33
97
•••••••
Step-by-step explanation:
sum of 65/12 and 8/3
65/12+8/3
taking LCM of 3 and 12 = 12
(65+8×4)/12
(65+32)/12
97/12
difference of 65/12 and 8/3
65/12-8/3
taking LCM of 3 and 12 = 12
(65-8×4)/12
(65-32)/12
33/12
divide of 97/12 and 33/12
(97/12)/(33/12)
97/33