Math, asked by chandan657, 6 months ago

divide the sum of 65upon12 and 8 upon 3 by their differences​

Answers

Answered by KrishnaKumar01
1

Answer:

Answer:

Divide the sum of 65/12 and 8/3 by their difference =\frac{97}{33}

33

97

Step-by-step explanation:

Let A=\frac{65}{12}\: and \: B = \frac{8}{3}A=

12

65

andB=

3

8

i ) Sum =A+B = \frac{65}{12}+\frac{8}{3}A+B=

12

65

+

3

8

=\frac{65+32}{12}

12

65+32

=\frac{97}{12}

12

97

---(1)

ii) Difference = A-B=\frac{65}{12}-\frac{8}{3}A−B=

12

65

3

8

=\frac{65-32}{12}

12

65−32

=\frac{33}{12}

12

33

---(2)

According to the problem given,

\frac{A+B}{A-B}

A−B

A+B

= \frac{\frac{97}{12}}{\frac{33}{12}}

12

33

12

97

= \frac{97}{33}

33

97

Therefore,

Divide the sum of 65/12 and 8/3 by their difference =\frac{97}{33}

33

97

•••••••

Answered by shashiawasthi069
0

Step-by-step explanation:

sum of 65/12 and 8/3

65/12+8/3

taking LCM of 3 and 12 = 12

(65+8×4)/12

(65+32)/12

97/12

difference of 65/12 and 8/3

65/12-8/3

taking LCM of 3 and 12 = 12

(65-8×4)/12

(65-32)/12

33/12

divide of 97/12 and 33/12

(97/12)/(33/12)

97/33

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