Question

divide the sum of 7/15 and 5/12 by their difference please solve this urgent please​

Answer 1

Step-by-step explanation:

$sum = \frac{7}{15} + \frac{5}{12} = \frac{28}{60} + \frac{25}{60} = \frac{53}{60}$

$difference = \frac{7}{15} - \frac{5}{12} = \frac{28}{60} - \frac{25}{60} = \frac{3}{60}$

$so \: \frac{53}{60} \div \frac{3}{60} = \frac{53}{3}$

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Answer 2

The division of the sum of  $\frac{7}{15}$ and $\frac{5}{12}$ by their difference is $\frac{53}{3}$.

Given :

$\frac{7}{15}$ and $\frac{5}{12}$

To find:

Divide the sum of  $\frac{7}{15}$ and $\frac{5}{12}$ by their difference.

Solution:

Step 1: Add  $\frac{7}{15}$ and $\frac{5}{12}$ by taking LCM of denominator 15 and 12:

$\frac{7}{15}$ + $\frac{5}{12}$  = $\frac{7 \times 4 + 5 \times 5}{60}$  

$\frac{7}{15}$ + $\frac{5}{12}$  = $\frac{28 + 25}{60}$  

[LCM of denominator 15 and 12 = 60]

$\frac{7}{15}$ + $\frac{5}{12}$  = $\frac{53}{60}$

Sum of $\frac{7}{15}$ and $\frac{5}{12}$ = $\frac{53}{60}$

Step 2: Subtract  $\frac{7}{15}$ and $\frac{5}{12}$ by taking LCM of denominator 15 and 12:

$\frac{7}{15}$ - $\frac{5}{12}$  = $\frac{7 \times 4 - 5 \times 5}{60}$

$\frac{7}{15}$ - $\frac{5}{12}$  = $\frac{28 - 25}{60}$

[LCM of denominator 15 and 12 = 60]

$\frac{7}{15}$ - $\frac{5}{12}$  = $\frac{3}{60}$

Difference of $\frac{7}{15}$ and $\frac{5}{12}$ = $\frac{3}{60}$

Step 3: Divide $\frac{53}{60}$  and $\frac{3}{60}$:

$\frac{53}{60}$  ÷  $\frac{3}{60}$ = $\frac{53}{60} \times \frac{60}{3}$

$\frac{53}{60}$  ÷  $\frac{3}{60}$  = $\frac{53}{3}$

Hence, the division of the sum of  $\frac{7}{15}$ and $\frac{5}{12}$ by their difference is $\frac{53}{3}$.

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