Question

Divide the sum of 8/9 and 7/3 by their difference.Quotient will be​

Answer 1

Answer:

First we have to find the sum (65/12)+(8/3)

LCM of 12 and 3 is 12

Then,

(65×1)/(12×1)=(65/12)

and (8×4)/(3×4)=(32/12)

Now,

=(65+32)/12

=(97/12)

Now find the difference of (65/12)−(8/3)

LCM of 12 and 3 is 12

Then,

(65×1)/(12×1)=(65/12)

(8×4)/(3×4)=(32/12)

Now,

=(65−32)/12

=(33/12)

Now divide (97/12)÷(33/12)

=(97×12)×(12/33)

=(97×12)/(12×33)

=(97×1)/(1×33)

=(97/33)

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Answer 2

Answer:

It is asserted that the sum of digits follows a repeating sequence of length 9. This is so because for any decimal representation x, the number 10*x (ten times x) will have the same sum of digits. Multiplication by the base number 10 simply moves the digits one place to the left and puts a zero in the units place. More generally,