Question

divide the sum of-8 by 7 and 5 by 14 by their product.

Answer 1

Sum of  $\frac{-8}{7}$ and $\frac{5}{14}$ is:
$\frac{-8}{7} + \frac{5}{14}= \frac{-8 \times 2+5}{14}= \frac{-16+5}{14}= \frac{-11}{14}$

Product of  $\frac{-8}{7}$ and $\frac{5}{14}$ is:
$\frac{-8}{7} \times \frac{5}{14}= \frac{-8 \times 5 }{7 \times14}= \frac{-4 \times 5}{7 \times 7}= \frac{-20}{49}$

Division of sum and product:
$\frac{-11}{14}\ \div \ \frac{-20}{49}= \frac{-11}{14} \times \frac{49}{-20}= \frac{77}{40}$

So answer is $\frac{77}{40}$