Question

divide the sum of -9/4 and -8/3 by the its product
pls witg explanation
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Answer 1

Given values are :-

-9/3 & -8/3

${\sf{Their\: sum\: =\: -{\dfrac{9}{3}}\: +\: -{\dfrac{8}{3}}}}$

${\sf{=\: {\dfrac{-9\: +\: -8}{3}}}}$

${\sf{=\: {\dfrac{-17}{3}}}}$

${\sf{Their\: product\: =\: -{\dfrac{9}{3}}\: \times\: -{\dfrac{8}{3}}}}$

${\sf{=\: {\dfrac{-9\: \times\: -8}{3}}}}$

${\sf{=\: {\dfrac{72}{3}}}}$

Now,

Dividing their sum and product

${\sf{ {\dfrac{-17}{3}}\: \div\:{\dfrac{72}{3}} }}$

${\sf{=\: {\dfrac{-17}{3}}\: \times\: {\dfrac{3}{72}}}}$

= -0.23

${\huge{\fbox{\sf{\blue{Answer\: =\: -0.23}}}}}$