Question

Divide the sum of minus 9 by 4 and minus 8 by 3 by the differences of 13 by 8 and minus 7 by 16

Answer 1

Answer:

• Sum of - 9/4 and - 8/3 :

$\implies{\sf{ \left( {\dfrac{- 9}{4}} \right) + \left( {\dfrac{- 8}{3}} \right) }}$

$\implies{\sf{ {\dfrac{- 9}{4}} - {\dfrac{8}{3}} }}$

$\implies{\sf{ {\dfrac{- 9(3) - 8(4)}{12}}}}$

$\implies{\sf{ {\dfrac{- 27 - 32}{12}}}}$

$\implies{\sf{ {\dfrac{- 59}{12}}}}$

• Difference of 13/8 and - 7/16 :

$\implies{\sf{ \left( {\dfrac{13}{8}} \right) - \left( {\dfrac{- 7}{16}} \right) }}$

$\implies{\sf{ {\dfrac{13}{8}} + {\dfrac{7}{16}}}}$

$\implies{\sf{ {\dfrac{13(2) + 7(1)}{16}}}}$

$\implies{\sf{ {\dfrac{26 + 7}{16}}}}$

$\implies{\sf{ {\dfrac{33}{16}}}}$

• Dividing the sum and difference :

$\implies{\sf{ {\dfrac{ {\dfrac{- 59}{12}} }{ {\dfrac{33}{16}} }} }}$

$\implies{\sf{ {\dfrac{- 59}{12}} \times {\dfrac{16}{33}} }}$

$\implies{\sf{ {\dfrac{- 59}{3}} \times {\dfrac{4}{33}} }}$

$\implies{\sf{ {\dfrac{- 236}{99}}}}$

Hence, the final answer is ${\bf{ {\dfrac{- 236}{99}} }}$.

Answer 2

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