Question

divide the sun of 65/9 and -11/-3 by the product of 7/6 and 5/-3.

Answer 1

first add 65/9 + -11/-3.you will get some answer.Let us suppose the answer is x.
similarly multiply 7/6 and 5/-3.You will get another answer. Let the answer is y.
Now divide x/y.

Answer 2

We have to divide the sum of $\frac{65}{9}$ and $\frac{-11}{-3}$ by the product of $\frac{7}{6}$ and $\frac{5}{-3}$. 
Oh! $\frac{-11}{-3}$ is the same as $\frac{11}{3}$. 
First, let's find the sum of $\frac{65}{9}$ and $\frac{11}{3}$. 
$\frac{65}{9} + \frac{11}{3}$
$= \frac{65+33}{9}$
$= \frac{98}{9}$

Now, let's find the product of $\frac{7}{6}$ and $\frac{5}{-3}$. 
I am using '*' for showing multiplication. 
$\frac{7}{6} * \frac{5}{-3}$
$= \frac{35}{-27} or \frac{-35}{27}$

Now, we are going to divide our results. 
$\frac{ \frac{98}{9} }{ \frac{-35}{27} }$
$= \frac{98}{9} * \frac{27}{-35}$
$= - \frac{42}{5}$

$- \frac{42}{5}$ is answer.