Question

divide the variable x^2+9x+20÷(x+4) ​

Answer 1

Answer:

$\frac{ {x}^{2} + 9x + 20}{x + 4} \\ \\ = \frac{ {x}^{2} + (5 + 4)x + 20}{x + 4} \\ \\ = \frac{ {x}^{2} + 5x + 4x + 20 }{x + 4} \\ \\ = \frac{x(x + 5) + 4(x + 5)}{x + 4} \\ \\ = \frac{(x + 4)(x + 5)}{x + 4} \\ \\ = x + 5$

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Answer 2

Answer:

x+5 is the correct answer

hope you get it

no explanation