Question

divide using factorisation: (4u^2+25u-21) /(u+7)​

Answer 1

Answer:

4u-3

Step-by-step explanation:

4u²+25u-21

4u²+28u-3u-21

4u(u+7)-3(u+7)

(4u-3) (u+7)

So, answer is 4u-3

Answer 2

Answer:

Required factor is $4u - 3$

Step-by-step explanation:

Given,

$\frac{4 {u}^{2} + 25u - 21 }{u + 7} \\ = \frac{4 {u}^{2} + (28 - 3)u - 21}{u + 7} \\ = \frac{4 {u}^{2} + 28u - 3u - 21 }{u + 7} \\ = \frac{4u(u + 7) - 3(u + 7)}{u + 7} \\ = \frac{(u + 7)(4u - 3)}{u + 7} \\ = 4u - 3$

This is a problem of Algebra.

Some important Algebra formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x - + y)( {x}^{2} - xy + {y}^{2} )$

Know more about Algebra,

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