Question

divide using factorisation method (x²+3x-xb-3b)+(x+3)​

Answer 1

Answer:

(x²+3x-xb-3b)/(x+3)

=(x(x+3)-b(x+3))/(x+3)

=((x+3)(x-b))/(x+3)

=(x-b)

I hope it will help you

Answer 2

Question ⤵

divide using factorisation method (x²+3x-xb-3b)

+(x+3)

Solution⤵

Given :- (x²+3x-xb-3b)+(x+3)

$(x {}^{2} + 3x + xb - 3b) + ( x + 3) \\ = (x( x+ 3) - b( x + b)) \div ( +x + 3) \\ = (x + b) (x + 3) \div (x + 3) \\ = (x + b)$

Answer⤵

➡ ( x + b)

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