divide using the factorization method (2x+3y)²-(a+b)² by (2x+3y-a-b)
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1
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2
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The given expression (2x+3y)(2x−3y) can be expanded as shown below:
(2x+3y)(2x−3y)
=[(2x×2x)+(2x×−3y)+(3y×2x)+(3y×−3y)]
=4x
2
−6xy+6xy−9y
2
=4x
2
−9y
2
Hence (2x+3y)(2x−3y)=4x
2
−9y
2
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