divide with linear method y² + 216 ÷(y-6)
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0
Answer:
Explanation:
In a division of
p
n
(
x
)
by
(
x
−
x
0
)
we have
p
n
(
x
)
=
(
x
−
x
0
)
q
n
−
1
(
x
)
+
r
0
where
q
n
−
1
(
x
)
is the quotient and
r
0
is the remainder. In our case we have
p
3
(
y
)
=
y
3
+
216
so the quotient will have the structure
q
2
(
y
)
=
y
2
+
a
y
+
b
and
r
0
=
c
then equating
y
3
+
216
=
(
y
+
6
)
(
y
2
+
a
y
+
b
)
+
c
grouping the coefficients
⎧
⎪
⎨
⎪
⎩
216
−
6
b
+
c
=
0
6
a
+
b
=
0
6
+
a
=
0
solving for
a
,
b
,
c
(
a
=
−
6
,
b
=
36
,
c
=
0
)
Hint.
c
=
0
warns us that
(
y
+
6
)
is a factor of
y
3
+
216
Finally
q
2
(
y
)
=
y
2
−
6
y
+
36
Answered by
0
Answer:
Confusing Question .
Step-by-step explanation:
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