Divide without finding the remainder theorem
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Answered by
3
Let x+1=0
x= -1
3(-1)^2+(-1)-1
3-1-1
3-2
=1
Remainder is 1
x= -1
3(-1)^2+(-1)-1
3-1-1
3-2
=1
Remainder is 1
Answered by
0
Given p(x) = 3x^2 + x - 1.
Given g(x) = x + 1.
Zero of the polynomial is g(x) = 0
⇒ x + 1 = 0
⇒ x = -1.
Therefore, p(-1) = 3(-1)^2 + (-1) - 1
= 3 - 1 - 1
= 1.
By remainder theorem, the remainder is 1.
Hope this helps!
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