Divide x+1 with 2xcube+3xsquare+x+5
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find the zero of the polynomial x+1,
x+1=0
x=-1
using remainder theorem,
substitute x=-1 in p(x),
p(x)=2x^3+3x^2+x+5
p(-1)=2(-1)^3+3(-1)^2+(-1)+5
p(-1)=-2+3-1+5
p(-1)=5
p(x)=5
x+1=0
x=-1
using remainder theorem,
substitute x=-1 in p(x),
p(x)=2x^3+3x^2+x+5
p(-1)=2(-1)^3+3(-1)^2+(-1)+5
p(-1)=-2+3-1+5
p(-1)=5
p(x)=5
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