Question

Divide (x

2 – 6x + 9) by (x – 3)​

Answer 1

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Answer 2

The quotient when the ${x}^{2} - 6x + 9 \: divided \: by \: x - 3$ is (x-3).

Given:

${x}^{2} - 6x + 9$

To Find:

The quotient when the ${x}^{2} - 6x + 9 \: divided \: by \: x - 3$

Solution:

To find the quotient we will follow the following steps:

As we know,

When the (x-3) divides the function completely then it leaves no remainder.

Now,

First, make factors of the quadratic equation.

So,

${x}^{2} - 6x + 9 = {x}^{2} - 3x - 3x+ 9 = x(x - 3) - 3(x - 3) = (x - 3)(x - 3)$

When divided by ( x-3) one of the factors will cancel and only one (x-3).

Henceforth, The quotient when the ${x}^{2} - 6x + 9 \: divided \: by \: x - 3$ is (x-3).

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