Math, asked by sanginenivishnuteja, 26 days ago

divide x^3-2x^2-5x+4 by (x-2)​

Answers

Answered by atharvamishra24
0

Answer:

To check that x−2 is the factor of x

3

−2x

2

−5x+4:

The value of x−2=0 ⟹ x=2.

So, put x=2 in expression, we get,

f(x)=x

3

−2x

2

−5x+4

f(2)=(2)

3

−2(2)

2

−5(2)+4

⇒f(2)=8−2×4−5×2+4

⇒f(2)=8−8−10+4

⇒f(2)=−6.

Remainder is not 0, when x−2 divides the polynomial x

3

−2x

2

−5x+4.

Thus x−2 is not a factor of polynomial x

3

−2x

2

−5x+4.

Answered by Mysteryboy01
0

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