Math, asked by kakiprince3, 1 year ago

divide x^3 + 2x^2 - 5x - 6 by x-1 using long division

Answers

Answered by Anonymous
4

Step by step solution :

Step 1 :

Equation at the end of step 1 :

Step 2 :

x3 - 2x2 - 5x + 6

Simplify —————————————————

x - 1

Checking for a perfect cube :

2.1 x3 - 2x2 - 5x + 6 is not a perfect cube

Trying to factor by pulling out :

2.2 Factoring: x3 - 2x2 - 5x + 6

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: -5x + 6

Group 2: x3 - 2x2

Pull out from each group separately :

Group 1: (-5x + 6) • (1) = (5x - 6) • (-1)

Group 2: (x - 2) • (x2)

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Answered by Anonymous
21

\huge\red{\mathfrak{Answer}}

x - 1) {x}^{3}  + 2 {x}^{2}  - 5x - 6(  {x}^{2} + 3x +10 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  {x}^{3}   -  {x}^{2}  \\ \:  \:  \:  \:  \:  \:  \:  \: --------- \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   {3x}^{2}  - 5x \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  {3x}^{2}  - 15x \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  ---------  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   - 10x - 6 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: 10x - 6 \\  \:  \:  \:  \:  \:  \:  \:  \:  \: ---------  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \: \:  \:  \: \:  \:  \: 4

Therefore, x²+3x+10

#BeBrainly

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