Question

divide x^3+3x^2-4x +7 by x-4​

Answer 1

Step-by-step explanation:

Here, p(x)=4x4−3x3−3x2+x−7, and the zero of 1−2x is 21

So, p(21)=4(21)4−3(21)3−3(21)2+(21)−7

                =41−83−43+21−7

                =82−3−6+4−56=−859

So, by the Remainder Theorem −859 is the remainder when 4x4−3x3−3x2+x−7 is divided by 1−2x.