divide x^3-3x^3+3X-2 by x-2
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Correct question :
- Divide x³ -3x² + 3x -2 by x - 2
Given :
- p ( x ) = x³ -3x² + 3x -2
- g ( x ) = x - 2
To Find :
- Remainder of the equation
Solution :
➨ x - 2 = 0
➨ x = 2
Now put value of x in x³ - 3x² + 3x - 2
➨ x³ - 3x² + 3x - 2
➨ 2³ - 3*2² + 3*2 - 2
➨ 8 - 12 + 6 - 2
➨ 14 - 14
➨ 0
when we divide x³ - 3x² + 3x - 2 by x - 2 it gives 0 as remainder
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