Question

Divide x^3+4x^2 -3x-10 by x+1 and verify your remainder by remainder theorem

Answer 1

hey mate,this is the answer

Answer 2

x³+4x²-3x-10 ÷ x+1 = x²+3x-6

GIVEN: Dividend x³+4x² -3x-10 and Divisor x+1
TO FIND: Quotient and Remainder
SOLUTION:

As we know using the Long Division Method,

The solution is attached to the image below.

Quotient =   x²+3x-6

Remainder = -4

And for verifying we use the Remainder Theorem,

That is,

Dividend = Divisor * Quotient + Remainder.

Taking the right-hand Side of the equation,

= Divisor * Quotient + Remainder

= ( x+1 ) ( x²+3x-6 ) + (-4)

= x³ + x² + 3x² + 3x - 6x - 6 +(-4)

= x³+4x²-3x-10

= Divisor

= Right-Hand Side of the equation.

Therefore,

x³+4x²-3x-10  = ( x+1 ) ( x²+3x-6 ) + (-4)

Is verified by the Remainder Theorem.

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